Question

Part A Write an equation for the reaction between NaOH and KHP. Write an equation for the reaction between and . NaOH+KHC8H4O4→Na++K++HC8H4O2−4+OH− NaOH+2KHC8H4O4→Na++K++2C8H4O2−4+2H2O NaOH+2KHC8H4O4→Na++K++2HC8H4O2−4+2OH− NaOH+KHC8H4O4→Na++K++C8H4O2−4+H2O Request Answer Part B The titration of 0.5516 g of KHP required 25.82 mL of an NaOH solution to reach the equivalence point. What is the concentration of the NaOH solution? Express your answer using four significant figures. [NaOH][ N a O H ] = nothing M Request Answer Provide Feedback

Answer 1

Answer: The molarity of NaOH solution is 0.1046 M.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of KHP = 0.5516 g

Molar mass of KHP = 204.22 g/mol

Putting values in equation 1, we get:

$\text{Moles of KHP}=\frac{0.5516g}{204.22g/mol}=0.0027mol$

The chemical reaction for the reaction of KHP and NaOH follows

$KHC_8H_4O_4(aq.)+NaOH\rightarrow KNaC_8H_4O_4(aq.)+H_2O(l)$

By Stoichiometry of the reaction:

1 mole of KHP reacts with 1 mole of NaOH.

So, 0.0027 moles of KHP will react with = $\frac{1}{1}\times 0.0027=0.0027mol$ of NaOH.

To calculate the molarity of NaOH, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

We are given:

Moles of NaOH = 0.0027 moles

Volume of solution = 25.82 mL  = 0.02582L      (Conversion factor:  1L = 1000 mL)

Putting values in above equation, we get:

$\text{Molarity of NaOH }=\frac{0.0027mol}{0.02582L}=0.1046M$

Hence, the molarity of NaOH solution is 0.1046 M.

Answer 2

Based on the data provided, the balanced equation of the reaction is:

• NaOH + KHC8H4O4 ---> KNaC8H4O4 + H2O
• the molarity of NaOH solution is 0.105 M.

What is the equation of the reaction between KHP and NaOH?

The equation of the reaction between KHP and NaOH is given below as:

• NaOH + KHC8H4O4 ---> KNaC8H4O4 + H2O

From the equation of reaction, mole ratio of KHP and NaOH is 1 : 1

Moles of KHP = mass/molar mass

molar mass of KHP = 204 g/mol

Moles of KHP = 0.5516/204

Moles of KHP = 0.00271 moles

• At equivalence point, moles of KHP = moles of NaOH

Moles of NaOH = molarity × volume

Volume of NaOH = 25.82 mL = 0.02582 L

0.00271 = molarity × 0.02582

Molarity = 0.00271/0.02582

Molarity of KOH = 0.105 M

Hence, the molarity of NaOH solution is 0.105 M.

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