Question

1. Simplify 43x2y4)
- Show your work
(2x2,5)". Sho
Answer:
27 over
4x^2y^8

Answer 1

Answer:

$\frac{27}{4x^6y^8}$

Step-by-step explanation:

Given:

$\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$

$(a^b)^c = a^{b.c}$ and

$\frac{x^a}{x^b} = x^{a - b}$

We use the above two rules to solve the problem.

So, $\frac{4 (3^4 . x^6 . y^{12})}{2^4. x^{12} .y^{20}}$

$\implies \frac{3^3. x^6. y^{12}}{2^2. x^{12}. y^{20}}$

Using the second rule we get:

$\frac{3^3}{2^2. x^6. y^{12}}$

$= \frac{27}{4. x^6. y^8}$

Hence, the answer.