HI. Can you help???
The table shows the total distance a spider traveled after a light was turned on.

Between which two consecutive times was the average rate of change the greatest?
Question 3 options:

A. between Second 11 and Second 15

B.between Second 19 and Second 28

C. between Second 5 and Second 11

D.between Second 15 and Second 19

HI Can you help The table shows the total distance a spider traveled after a light was turned on Between which two consecutive times was the average rate of cha class=

Respuesta :

Answer:

The maximum rate of change is between second 15 and second 19.

Step-by-step explanation:

See the attached table.

The table shows the total distance a spider traveled after a light was turned on.

Now, the average rate of change between two consecutive times in the table is given by  

= [tex]\frac{\textrm {Total change in Distance in feet}}{\textrm {Total change in Time in seconds }}[/tex]

Therefore, between second 5 and second 11, the average rate of change = [tex]\frac{7 - 4}{11 - 5} = 0.5[/tex]

Between second 11 and second 15, the average rate of change = [tex]\frac{13 - 7}{15 - 11} = 1.5[/tex]

Between second 15 and second 19, the average rate of change = [tex]\frac{20 - 13}{19 - 15} = 1.75[/tex]

Between second 19 and second 28, the average rate of change = [tex]\frac{24 - 20}{28 - 19} = 0.44[/tex]

Therefore, the maximum rate of change is between second 15 and second 19. (Answer)

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