Question

if a ball is thrown with a velocity of 25 m/s at an angle of 37 degrees above the horizontal,evaluate the projectile for it's horizontal component of the velocity​

Answer 1

Answer:100 mph

Explanation:

Answer 2

When an object is thrown in a trajectory path the motion is called projectile motion. The horizontal component for the given projectile motion is 15.04 m/s.

From the projectile motion:

$V_x = u\rm \ sin{\theta}$

Where,

$V_x$ - Velocity in the X-axis

$u$- initial velocity =25 m/s

$\theta$ =  angle of throw = 37 degrees

Put the values in the formula,

$V_x = 25\rm{\ sin} \ 37^o\\\\\it{ V_x} = \rm 25\rm \times -0.64\\\\\it {V_x} = \rm 15.04 \rm \ m/s$

Therefore, the horizontal component for the given projectile motion is 15.04 m/s.

Learn more about the projectile motion:

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