Question

Pleaseeeee helppppppp Simplify [3^-2]^4

Answer 1

Answer:

$\frac{1}{6561}$

Step-by-step explanation:

This is a "power" raised to another "power" problem. Lets see the rule of exponents that dictates solving this type of problem.

Power rule of Exponents:

$(a^b)^c=a^{bc}$

We basically multiply the powers together. So this problem becomes:

$[3^{-2}]^4=3^{-2*4}=3^{-8}$

We can use another property to make it simpler. The property is:

$a^{-b}=\frac{1}{a^b}$

So, the problem becomes:

$\frac{1}{3^8}=\frac{1}{6561}$

In fractional form, this is the answer:  $\frac{1}{6561}$