Answer:
Rate at which energy is being removed by the heat = 89.625 watts
Explanation:
P = (c₁m₁ + c₂m₂)ΔTₓ
Where P = rate at which energy is being removed by the heat, c₁ = specific heat capacity of water, m₁ = mass of water, c₂ = specific heat capacity of aluminium, m₁ = mass of aluminum, ΔTₓ = rate of temperature decrease.
Where c₂ = 900 J/kgK, m₁ = 800 g = 0.8 kg, m₂ = 250 g = 0.25 kg, c₁ = 4200 J/kgK, ΔTₓ = 1.5°C per minute
P =( 4200×0.8 + 900× 0.25)1.5
P = (3360 + 225 ) 1.5
P = (3585 )1.5
P = 5377.5 J/ min.
P = 5377.5/60 = 89.625 watts.
Rate at which energy is being removed by the heat = 89.625 watts
