Answer:
given,
mass of the glider = 0.250 Kg
force constant = k = 4.6 N/m
x = 0.1 m
a) Using conservation of energy
K E = PS
[tex]\dfrac{1}{2}mv^2 =\dfrac{1}{2}kx^2[/tex]
[tex]v =\sqrt{\dfrac{kx^2}{m}}[/tex]
[tex]v =\sqrt{\dfrac{4.6\times 0.1^2}{0.25}}[/tex]
v = 0.428 m/s
b) now, calculation of displacement
Using conservation of energy
K E = PS
[tex]\dfrac{1}{2}mv^2 =\dfrac{1}{2}kx^2[/tex]
[tex]x =\sqrt{\dfrac{mv^2}{k}}[/tex]
[tex]x =\sqrt{\dfrac{0.25\times 2.6^2}{4.6}}[/tex]
x= 0.606 m