A 0.47 kg mass is attached to a spring with a spring constant of 130 N/m so that the mass is allowed to move on a horizontal friction-less surface. The mass is released from rest when the spring is compressed 0.12 m. A) Find the force on the mass at the instant the spring is released. B) Find the acceleration of the mass at the instant the spring is released.

Respuesta :

Answer:

F= 15.6 N,   a= 33.2 m/s^2

Explanation:

mass= m = 0.47 kg

spring constant= k = 130N/m

spring compression = x = 0.12 m

a).

force on the mass= F = k*x

F = 130 * 0.12 N

F= 15.6 N

b).

Acceleration of mass= a=?

F= ma

a=F / m

a= 15.6/ 0.47 m/s^2

a= 33.2 m/s^2