Answer: (x + 1 )(x+5)
Step-by-step explanation:
Given :
[tex]x^{2}[/tex] + 6x + 5
Compare with the general quadratic equation:
a[tex]x^{2}[/tex] + bx + c
To factorize , you are to find two numbers that multiply to give ac , and add to give b.
After which you will re - write the middle number with those numbers.
From the given question , ac = 5[tex]x^{2}[/tex] , we are to find two numbers that will multiply to give 5[tex]x^{2}[/tex] and add to give 6x.
The numbers are 1x and 5x.
We will then replace the middle number by the two numbers , that is
[tex]x^{2}[/tex] + x + 5x + 5
x(x+1) +5( x +1)
(x+1)(x+5)
