Question

Which graph represents the solution set to the system of inequalities?

{y≤14x−2y≥−54x+2



Coordinate graph showing a range of negative five and five on both axes. A solid line through begin ordered pair 0 comma 2 end ordered pair and begin ordered pair 4 comma negative 3 end ordered pair. Another solid line through begin ordered pair 0 comma negative 2 end ordered pair and begin ordered pair 4 comma negative 1 end ordered pair. Four regions are created by the intersection of the two lines. The right region is the shaded region.

Coordinate graph showing a range of negative five and five on both x and y axes. A solid line through begin ordered pair 0 comma 2 end ordered pair and begin ordered pair 4 comma negative 3 end ordered pair. A dashed line through begin ordered pair 0 comma negative 2 end ordered pair and begin ordered pair 4 comma negative 1 end ordered pair. Four regions are created by the intersection of the two lines. The upper right region is the shaded region.

Coordinate graph showing a range from negative seven to three on both x and y axes. A solid line through begin ordered pair 0 comma 2 end ordered pair and begin ordered pair negative 4 comma negative 3 end ordered pair. A dashed line through begin ordered pair 0 comma negative 2 end ordered pair and begin ordered pair negative 4 comma negative 3 end ordered pair. Four regions are created by the intersection of the two lines. The lower left region is the shaded region.

Coordinate graph showing a range of negative five to five on both x and y axes. A solid line through begin ordered pair 0 comma 2 end ordered pair and begin ordered pair negative 4 comma negative 3 end ordered pair. A dashed line through begin ordered pair 0 comma negative 2 end ordered pair and begin ordered pair 4 comma negative 1 end ordered pair. Four regions are created by the intersection of the two lines. The upper left region is the shaded region.

Answer 1

Answer:

The right region is the shaded region.

see the attached figure

Step-by-step explanation:

we have

$y\leq \frac{1}{4}x-2$ ----> equation A

The solution of the inequality A is the shaded area below the solid line $y=\frac{1}{4}x-2$

The slope of the solid line is positive

The y-intercept of the solid line is (0,-2)

The x-intercept of the solid line is (8,0)

$y\geq -\frac{5}{4}x+2$ ----> equation B

The solution of the inequality B is the shaded area above the solid line $y=-\frac{5}{4}x+2$

The slope of the solid line is negative

The y-intercept of the solid line is (0,2)

The x-intercept of the solid line is (1.6,0)

using a graphing tool

Four regions are created by the intersection of the two lines

The right region is the shaded region.

see the attached figure

Answer 2

Answer:

i go to k12 too

Step-by-step explanation: