Answer:
The distance in meters traveled by the drag racer in 6 seconds is 180.
Explanation:
Given:
A drag racer starts from rest. So, initial velocity of the drag racer, [tex]v_i=0[/tex]
Time taken is, [tex]t=6\ s[/tex]
Acceleration of the drag racer is, [tex]a=10\ m/s^2[/tex]
Now, we are asked to find how far will he reach in 6 seconds. So, we are asked the displacement, 'd'.
We use the following kinematic equation to find 'd'.
[tex]d=v_it+\frac{1}{2}at^2[/tex]
Plug in the given values and solve for 'd'. This gives,
[tex]d=0+\frac{1}{2}(10)(6)^2\\d=5\times 36\\d=180\ m[/tex]
Therefore, the distance in meters traveled by the drag racer in 6 seconds is 180.