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Simplify fourth root of 6 over fifth root of 6. 6 to the power of one fifth 6 to the power of nine twentieths 6 to the power of one twentieth 6 to the power of five fourths

Respuesta :

Answer:

[tex]\sqrt[20]{6}[/tex]

[tex]\sqrt[60]{6^{137} }[/tex]

Step-by-step explanation:

We have to simplify the followings:

1) [tex]\frac{\sqrt[4]{6} }{\sqrt[5]{6} }[/tex] and

2) [tex]6^{\frac{1}{5}} \times 6^{\frac{9}{12}} \times 6^{\frac{1}{12}} \times 6^{\frac{5}{4}}[/tex]

1) Now, [tex]\frac{\sqrt[4]{6} }{\sqrt[5]{6} }[/tex]

= [tex]\frac{6^{\frac{1}{4}}}{6^{\frac{1}{5}}}[/tex]

= [tex]6^{(\frac{1}{4} - \frac{1}{5})}[/tex]

{Since, [tex]\frac{a^{b}}{a^{c}} = a^{(b - c)}[/tex] }

= [tex]6^{(\frac{5 - 4}{20})}[/tex]

= [tex]6^{\frac{1}{20}}[/tex]

= [tex]\sqrt[20]{6}[/tex] (Answer)

2) [tex]6^{\frac{1}{5}} \times 6^{\frac{9}{12}} \times 6^{\frac{1}{12}} \times 6^{\frac{5}{4}}[/tex]

= [tex]6^{(\frac{1}{5} + \frac{9}{12} + \frac{1}{12} + \frac{5}{4})}[/tex]

= [tex]6^{(\frac{12 + 45 + 5 + 75}{60})}[/tex]

{Since, [tex]a^{b} \times a^{c} = a^{(b + c)}[/tex]}

= [tex]6^{\frac{137}{60}}[/tex]

= [tex]\sqrt[60]{6^{137} }[/tex] (Answer)

Answer:

6 1/20

Step-by-step explanation:

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