Answer: 0.036756909
Step-by-step explanation:
Formula for Binomial probability distribution.
[tex]P(x)=^nC_xp^x(1-p)^{n-x}[/tex]
, where x= number of success
n= total trials
p=probability of getting success in each trial.
According to the given information , we have
n= 10 , p= 0.30 and x= 6
Then, the required probability will be :
[tex]P(x=6)=^{10}C_6(0.3)^6(1-0.3)^{10-6}\\\\= \dfrac{10!}{6!(10-6)!}\times(0.3)^6(0.7)^4\\\\=\dfrac{10\times9\times8\times7\times6!}{6!4!}(0.3)^6(0.7)^4\\\\=(210)(0.000729)(0.2401)=0.036756909[/tex]
Hence, the required provability = 0.036756909
