Respuesta :
Answer:
First question:
Top 6%: 4.87 ounces
Bottom 6%: 4.75 ounces
Second question:
Top 7%: Score of 649.4.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
For the first problem, we have that:
[tex]\mu = 4.81, \sigma = 0.04[/tex]
Top 6%
The value of X when Z has a pvalue of 0.94. This is [tex]Z = 1.555[/tex]
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]1.555 = \frac{X - 4.81}{0.04}[/tex]
[tex]X - 4.81 = 1.555*0.04[/tex]
[tex]X = 4.8722[/tex]
Bottom 6%
The value of X when Z has a pvalue of 0.06. This is [tex]Z = 1.555[/tex]
For the second problem, we have that:
[tex]\mu = 496, \sigma = 109[/tex]
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]-1.555 = \frac{X - 4.81}{0.04}[/tex]
[tex]X - 4.81 = -1.555*0.04[/tex]
[tex]X = 4.7477[/tex]
Top 7%
The value of X when Z has a pvalue of 0.93. This is [tex]Z = 1.475[/tex]
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]1.475 = \frac{X - 496}{104}[/tex]
[tex]X - 496 = 104*1.475[/tex]
[tex]X = 649.4[/tex]