Question

Now the oil is replaced with a height h3 = 0.28 m of glycerin which has a density of 1261 kg/m3. Assume the glycerin does not mix with the water and the total volume of water is the same as before. Now what is the absolute pressure in the water at the interface between the water and glycerin?

Answer 1

Answer: 3460. 184 N/m2

Explanation:

Density of glycerin = 1261kg/m3

Length of glycerin= 0.28m

Now, volume of water remain constant, so nothing changes, moreover, the water and glycerin did not mix, what changes is the pressure at the interface

Now Pressure P= Force F/Area A

I.e P = F/A-------1

Recall F = Mg where g is acceleration constant taken as 9.8m/s2

Density D = Mass M/Volume V

I.e D = M/V--------2

Recall Volume = Area × height or (length)

I.e V = A × h----------3

Replace V in equation 2 with A and h and D with 1261

1261 = M/0.28A hence

M = 1261 × 0.28A

= 353.08Akg

Replace 353.08A with M in equation 1 :

P = F/A = Mg/A = 353.08A × 9.8/A

Now A cancel A

P= 353.08 × 9.8

=3460.184N/m2

I hope this answer the problem. Thank you.