Question:
At noon a tank contains 6 cm of water after several hours it contains 3 cm of water what is the percent decrease of water in the tank
Answer:
The percent Decrease of water in the tank is 50%
Step-by-step explanation:
Given:
Initial amount of water in the tank at the noon = 6 cm
amount of water remained in water after several hours = 3 cm
To Find:
The percent decrease =?
Solution:
The percent decrease in the tank
=>[tex]\frac{\text {water present after some hours }}{\text {initial water contained in the tank }} \times 100[/tex]
Substituting the values
=>[tex]\frac{3}{6} \times 100[/tex]
=>[tex]\frac{1}{2} \times 100[/tex]
=>[tex]\frac{100}{2}[/tex]
=> 50
