Answer:
3801.13 N
Explanation:
Pressure exerted on a surface is equivalent to applied force divided by the cross sectional area. Then, the applied force will be equal to the product of the pressure exerted and the cross sectional area.
Where given:
Atmospheric pressure (P1) = 1.013*10^5 Pa
T1 = 20+273.15 = 293.15 K
P2 = ?
T2 = 120+273.15 = 393.15 K
Using the gas equation: P1/T1 = P2/T2
Therefore, P2 = P1*T2/T1 = 1.013*10^5 *393.15/293.15 = 13.6*10^4 Pa
The net pressure = P2 - P1 = 13.6*10^4 - 1.013*10^5 = 34.6 kPa
The net force [tex]F_{120} = net pressure * area[/tex]
Area = 0.11 m^2
Thus:
The net force [tex]F_{120} = 34555.7*0.11[/tex] = 3801.13 N
