Answer:
a.
The hypothesis Null and alternative can be formulate as a :
H0 = μ = 7.5 hr / week
Hₐ = μ < 7.5 hr / week
b.
The Null hypothesis is true and the administrator believes that the college freshman dot not spend 7.5 hours
E(x) = μ = 7.5 hr / week
SE (x) = σ / √ n = 9 / √100
SE (x) = 0.9
Z' = 6.6 - 7.5 / SE
Z' = 6.6 -7.5 / 0.9 = -1
The empirical rule in this case is use
% = (100 - 68 ) / 2 = 16%
c.
There is not strong arguments of Null Hypothesis so can be accept the H0 and is no significantly different from the report of 7.5 hr / week