Respuesta :

Answer:

Explanation:

Given

In R-L-C circuit frequency is very high

Inductive Reactance for inductor is given by [tex]X_L=2\pi f\cdot L[/tex]

Inductive Reactance for Capacitor is given by [tex]X_c=\frac{1}{2\pi f\cdot C}[/tex]

as frequency becomes too high then [tex]X_L[/tex] will become very large and and [tex]X_c [/tex]will be approximately zero .

In other words inductor behave as a very high resistance and Capacitor behaves as very small resistance                            

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