Respuesta :

Answer:

Volume occupied by 10 grams of Lithium Oxide at STP is 7.52 L

Explanation:

STP (Standard Temperature and Pressure) : It is used while performing calculation on gases and provide standards of measurements while performing experiment.

According to IUPAC (International Union of Pure And applied Chemistry) , standard temperature is 273.15 K and Pressure is 100 kPa (0.9869 atm). At STP condition 1 mole of substance occupies 22.4 L volume .

Molar mass of Lithium Oxide = 29.8 g/mol

[tex]Li_{2}O[/tex] = 2(6.9) + 15.99 = 29.8

Mass of 1 mole [tex]Li_{2}O[/tex] = 29.8 g

1 mole [tex]Li_{2}O[/tex] occupies, Volume = 22.4 L

29.8 g [tex]Li_{2}O[/tex] occupies, V = 22.4 L

1 g [tex]Li_{2}O[/tex] occupies ,V = [tex]\frac{22.4}{29.8}[/tex]

1 g [tex]Li_{2}O[/tex] occupies ,V = 0.7516 L

10 g tex]Li_{2}O[/tex] occupies ,V = [tex]0.7516 \times10[/tex] L

V = 7.52 L

So, volume occupied by Lithium Oxide At STP is 7.52 L

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