Answer:
The quantity of heat required to to heat the cup of water through a temperature change of 80°C = 200.83 kJ
Explanation:
Density = mass/Volume.
∴ mass = Density × volume
Where Density of water = 1.00 g/mL, volume of water = 600 mL
Mass = 1 × 600 = 600 g.
(Q) = cm(ΔT)...................... equation 1
Where Q = quantity of heat, c = specific heat capacity of water, m = mass of water, ΔT = T₁-T₂ = change in temperature.
Where c = 4.184 J/g°C, m = 600 g, ΔT = T₁-T₂ = 100 - 20 = 80°C
Substituting these values into equation 1,
Q = 4.184 × 600 × 80
Q = 200832 J = 200.83 kJ
Therefore the quantity of heat required to to heat the cup of water through a temperature change of 80°C = 200.83 kJ
