Question

Help Please ! A fisherman casts his lure at an angle of 33 degrees above the horizontal. The lure reaches a maximum height of 2.3 m. Assuming no frictional forces, what was the initial velocity the fisherman gave the lure when he cast it?

12.34 m/s


28.45 m/s


34.91 m/s


21.29 m/s

Answer 1

The initial velocity is 12.34 m/s

Explanation:

The vertical component of the initial velocity determines the maximum height.

The formula to apply is : v²=u²+2as , where

v=y-component, final velocity = 0 m/s

u= y-component of the initial velocity = ?

s= distance traveled = 2.3 m

a=acceleration due to gravity = -9.81 m/s²

Using the values in the equation

v²=u²+2as

0²=u²+2×2.3×-9.81

0=u²-45.126

45.126=u²

√45.126= u

6.7175 m/s

The vertical component of velocity is given by;

velocity*sin(angle with horizontal)

velocity=6.7175 / sin 33°

=12.338 m/s

=12.34 m/s

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Finding Initial velocity :https://brainly.com/question/1858995

Keywords : angle, maximum height, initial velocity, friction

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