Answer:
Total 25.45 hours will be taken to empty the pool.
Step-by-step explanation:
Time taken by large pumpkin to empty the pool=40 hours
Time taken by the smaller pumpkins to empty the pool=70 hours
Amount of pool emptied by large pumpkin in one hour=[tex]\frac{1}{40}[/tex]
Amount of pool emptied by small pumpkin in one hour=[tex]\frac{1}{70}[/tex]
Amount of pool emptied in one hour if both pumpkins work together=
[tex]\frac{1}{40}[/tex]+ [tex]\frac{1}{70}[/tex]
=[tex]\frac{11}{280}[/tex]
Therefore, the no. of days will be the reciprocal of the amount of work done in one hour ie . [tex]\frac{280}{11}[/tex]
Total 25.45 hours will be taken to empty the pool.