Question

Find k so that the three equations 3x-y=2, 2x+8=3y and y=kx common solution

Answer 1

Answer:

$k=2$

Step-by-step explanation:

Given:-

$3x-y=2$----------------(Equation 1)

$2x+8=3y$-------------(Equation 2)

By solving Equation 1 we get,

$3x-y=2$

$y=3x-2$---------------(Equation 3)

Now substituting equation 3 in equation 2,

$2x+8=3y$

$2x+8=3\time (3x-2)$

$2x+8=9x-6$

$7x=14$

$x=2$---------------(Equation 4)

Now substituting equation 4 in equation 3 we get,

$y=3x-2$

$y=(3\times 2)-2$

$y=6-2$

$y=4$--------------(Equation 5)

Now,

$y=kx$

$k=\frac{y}{x}$

$k=\frac{4}{2}$

$k=2$

Therefore $k=2$