Respuesta :
Answer:
1. Increasing concentration of CO:
The concentration of the product, CO₂(g) increases (↑) and the concentration of the reactants, CO(g) and O₂(g) decreases (↓)
2. Increasing concentration of CO₂:
The concentration of the reactants, CO(g) and O₂(g) increases (↑) and the concentration of the product, CO₂(g), decreases (↓).
3. Decreasing the volume of the system:
The concentration of the product, CO₂(g) increases (↑) and the concentration of the reactants, CO(g) and O₂(g) decreases (↓).
Explanation:
According to the Le Chatelier's principle, for a given chemical reaction at equilibrium, a change in the concentration of any chemical species or volume causes the equilibrium of the reaction to shift in a direction, that minimizes the effect of the change.
Given reaction: 2CO(g) + O₂(g) ⇌ 2CO₂(g)
1. Increasing concentration of CO:
When the concentration of the reactant CO(g), increases; the equilibrium shifts towards the forward direction or product side, thereby increasing the concentration of the product, CO₂(g) and decreasing the concentration of the reactants, CO(g) and O₂(g).
2. Increasing concentration of CO₂:
When the concentration of the product CO₂(g), increases; the equilibrium shifts towards the backward direction or reactant side, thereby increasing the concentration of the reactants, CO(g) and O₂(g) and decreasing the concentration of the product, CO₂(g).
3. Decreasing the volume of the system:
When the volume of the system decreases, the pressure increases, thus causing the equilibrium of the reaction to shift in a direction that produces less number moles of gas.
Since, total number of moles of gaseous reactants and products is 3 and 2, respectively.
Therefore, when the volume of the system decreases; the equilibrium of the reaction shifts towards the forward direction or product side, thereby increasing the concentration of the product, CO₂(g) and decreasing the concentration of the reactants, CO(g) and O₂(g).