Answer:
169.98 m
Explanation:
[tex]\alpha[/tex] = Thermal coefficient of marble = [tex]2.5\times 10^{-6}/^{\circ}C[/tex]
[tex]L_0[/tex] = Initial length = 170 m
[tex]\Delta T[/tex] = Change in temperature = (-10-35)°C
Change in length is given by
[tex]\Delta L=\alpha L_0\Delta T\\\Rightarrow \Delta L=2.5\times 10^{-6}\times 170\times (-10-35)\\\Rightarrow \Delta L=-0.019125\ m[/tex]
The height on the given day will be [tex]170-0.019125=169.98\ m[/tex]