Answer:A) 220 nm
Explanation:
Given
Maximum Kinetic Energy [tex]K.E.=1.10 eV[/tex]
Work Function [tex]W=4.65 eV[/tex]
from Einstein Equation
[tex]h\mu =W+K.E.[/tex]
[tex]h\cdot \frac{c}{\lambda }=W+K.E.[/tex]
[tex]h\cdot \frac{c}{\lambda }=4.65+1.10[/tex]
[tex]6.626\times 10^{-34}\cdot \frac{3\times 10^8}{\lambda }=5.75[/tex]
[tex]1 eV=1.6\times 10^{-19} J[/tex]
thus [tex]5.75 eV=9.2\times 10^{-19} J[/tex]
[tex]\lambda =\frac{6.626\times 10^{-34}\time 3\times 10^8}{9.2\times 10^{-19}}[/tex]
[tex]\lambda =216.06 nm\approx 220 nm[/tex]