Answer:
Option A: Change the method call to displayName("Sean")
Explanation:
The function displayName(string name) expects an input string to be passed to its parameter name. The original pseudocode that call to the method, displayName() doesn't include an argument within the parenthesis. When the function is called, no value will be passed to the parameter name. This will make the name become undefined.
To fix the problem we need to include a string argument inside the parenthesis when calling the function displayName() so that the string argument (e.g. "Sean") will be passed to the parameter name and then the function will operate on the name and display it.