Question

please is phisics basic ekekekekekeek

Answer 1

Answer:

B) $R= \sqrt{(40N)^2+(30N)^2}$

Explanation:

Given $\sum Fx=40N\ \ \ \ \ \ \ \ \ \sum Fy=30N$

As the forces are on X and Y-axis. We can see the angle between the forces is 90°

Using vector addition formula. Since the angle between the forces is 90°

$R=\sqrt{\sum (Fx)^2+\sum (Fy)^2}$

$R= \sqrt{(40N)^2+(30N)^2}$

Please see the attachment.