Three taxi cabs make a complete trip from downtown to the airport and back in 15 , 33 and 55 minutes, respectively. If all three cabs leave at the same time, what is the shortest time that must pass before they are all together again?

Respuesta :

Answer:

165 minutes

Explanation:

We can break the numbers into prime numbers

15 = 3 * 5

33 = 3 * 11

55 = 5 * 11

The shortest time that must pass before they are all together again would be the least multiple that is divisible by all 3 number, which is

3 * 5 * 11 = 165

Hence after 165 minutes the 3 cars should all meet together again.

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