Answer:
a) Team A will win.
b) The losing team will accelerate towards the middle line with 0.01 m/[tex]s^{2}[/tex]
Explanation:
Given that Team-A pulls with a force , [tex]F_{1} = 50N[/tex]
and Team-B pulls with a force , [tex]F_{1} = 45N[/tex]
∵ [tex]F_{1} > F_{2}[/tex]
The rope will move in the direction of force [tex]F_{1}[/tex].
∴ Team-A will win.
b) Considering both the teams as one system of total mass , [tex]m = 246+253 = 499 kg[/tex]
Net force on the system , [tex]F = F_{1} - F_{2}[/tex] = 50-45 = 5N
Applying Newtons first law to the system ,
F = ma , where 'a' is the acceleration of the system.
Since , both the teams are connected by the same rope , their acceleration would be the same.
∴ 5 = 499×a
∴ a = 0.01 m/[tex]s^{2}[/tex]
