Respuesta :
Answer:
3750 J
Step-by-step explanation:
We are given that
Total number of cartons=10
Height of loading dock from the side walk=1.5 m
Length of ramp=10 m
Mass of each carton=25 kg
We have to find the work done by the delivery man on the cartons to move them to the loading dock.
Work done=[tex]Mgh[/tex]
Where M=Total mass of object
h=Height of object above the ground
g=Acceleration due to gravity=[tex]10m/s^2[/tex]
Total mass of cartons=M=[tex]10\times 25=250 kg[/tex]
h=1.5 m
Substitute the values then, we get
Work done=[tex]250\times 1.5\times 10=3750[/tex]J
Hence, the total work done by the deliverman on the cartons to move them to the loading dock=3750J
If assuming no friction done, the total work done by the deliveryman on the cartons to move them to the loading dock is 367.5 N.m approx
How to calculate the work done?
If the force applied on the object is 'F' newton, and the distance it travels is 'd' meters, then, the work done is calculated as:
[tex]W = F \times d \: \rm \: N.m[/tex]
For this case, assuming that the ramp is frictionless, all the work done by the deliveryman would be just to get the box up and up.
The force he applied was equal to the force of gravity, but in opposite direction.
The force of gravity is mass times gravitational acceleration.
Thus, [tex]F = m.g \approx 25\times 9.8 \: \: \rm kg.m/s^2 = 245 \: \: \rm kg.m/s^2[/tex]
The distance the object moved vertically up is 1.5 meters.
Thus, [tex]W = F.d \approx 245 \times 1.5 = 367.5 \: \rm N.m[/tex]
(horizontal work was 0 as no resistant force was there)
Thus, total work done = 367.5 N.m approx
Thus, if assuming no friction done, the total work done by the deliveryman on the cartons to move them to the loading dock is 367.5 N.m approx
Learn more about work here:
https://brainly.com/question/13061258
