Question

what is the acceleration of a 3kg rock thay is thrown with a force of 18N​

Answer 1

Answer:

Acceleration = 6 m/s²

Explanation:

Given:

Mass of the rock is, $m=3\ kg$

Force acting on the rock is, $F=18\ N$

From Newton's second law, we know that the net force acting on an object is equal to the product of its mass and the net acceleration. The acceleration of the object acts in the direction of the net force.

Acceleration is the rate of change of velocity.

Here, the mass and net force acting on the rock is given. So, we use Newton's second law to find its acceleration.

Therefore, from Newton's second law, the net force acting on the rock is given as:

$F=ma$

Rewriting in terms of 'a', we get

$a=\frac{F}{m}$

Plug in 18 N for 'F', 3 kg for 'm' and solve for 'a'. This gives,

$a=\frac{18\ N}{3\ kg}\\a=6\ m/s^2$

Therefore, the acceleration of the rock is 6 m/s² in the direction of the applied force.