Question

What is the equation of the line through (6, 3) and perpendicular to y=-x+2?
o y=-x-5
o y= ģx+2
o y= ge-5
o y=-x+

Answer 1

Answer: B. gx+2

Step-By-Step Explanation : Fund the negative reciprocal of the slope and the original line and use the point-slope formula y=y1=m(x-x1) to find the line perpendicular to y=-x+2.

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