Question

HELP!
There is a bag filled with marbles: 5 red, 8 blue, 4 yellow, and 3 green.

Question:
You want to draw a red then a blue marble. Do you have a better chance of drawing a red then a blue marble with or without replacing the first marble? Explain your answer.
(Not multiple choice)

Answer 1

Answer: You might redraw a blue one' there is only 5 red and 4 yelow and 3 green so automatically yellow and green are gone leaving red and blue but having a marbled of blu you got seven blue and five red your most likley going to get a blue one over a red one

Step-by-step explanation:

Answer 2

Answer: You have a better chance if you do not replace the red marble.

Step-by-step explanation:

The bag has:

5 red marbles

8 blue marbles

4 yellow marbles

3 green marbles

A total of 5 + 8 + 4 + 3 = 20

You want to draw a red marble and then a blue marble.

The probability of drawing a red marble in your first attempt is the number of red marbles divided the total number of marbles:

P1 = 5/20  

now you want to draw a blue marble.

If you replace the red marble, you have 20 marbles again in the bag, then the probability of drawing a blue marble is:

P2 = 8/20

The joint probability is P = P1*P2 = (5/20)*(8/20) = 0.1

If you do not replace the red marble, you have 19 total marbles in the bag, then the probability of taking a blue marble is:

P2 = 8/19

The joint probability is:

P = P1*P2 = (5/20)*(8/19) = 0.105

The probability is slightly bigger if you do not replace the red marble.