Question

Methane gas and oxygen gas react to form water vapor and carbon dioxide gas. What volume of water would be produced by this reaction if 3.6 L of methane were consumed? Also, be sure your answer has a unit symbol, and is rounded to the correct number of significant digits.

Answer 1

volume of H₂O = 7.2 L

Explanation:

The combustion reaction of methane (CH₄):

CH₄ + 2 O₂ → CO₂ + 2 H₂O

Now we calculate the number of moles of methane using the following formula:

number of moles = volume / 22.4 (L/mole)

number of moles of CH₄ = 3.6 / 22.4

number of moles of CH₄ = 0.16 moles

Taking in account the chemical reaction, we devise the following reasoning:

if             1 mole of CH₄ produce 2 moles of H₂O

then  0.16 moles of CH₄ produce X moles of H₂O

X = (0.16 × 2) / 1 = 0.32 moles of H₂O

And now we can calculate the volume of water (H₂O) produced by the reaction:

number of moles = volume / 22.4 (L/mole)

volume = number of moles × 22.4 (L/mole)

volume of H₂O = 0.32 × 22.4

volume of H₂O = 7.2 L

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combustion reaction

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