Answer:
The probability that both earrings are silver is 0.27.
Step-by-step explanation:
Basically, we have to pick in a such a way that the first earring is a silver earring and the second one is also a silver earring.
Constituents of the box= 7 silver, 6 gold.
Probability=[tex]\frac{No. Of Favorable Outcomes}{Total No. Of Outcomes}[/tex]
Therefore, probability of picking up a silver earring in the first attempt(A)= [tex]\frac{7}{13}[/tex]
As we have picked up, one earring from the bag, the no. of silver earrings have been decreased by 1 as have the total no. of earrings.
Therefore, the total no. of earrings now=12
No. of silver earrings in the bag now=6
Probability of picking up a silver in the second attempt after the above first attempt(B)=[tex]\frac{6}{12}[/tex]
P(A∩B)=P(A)*P(B)
=[tex]\frac{7}{13}[/tex] x [tex]\frac{6}{12}[/tex]
=[tex]\frac{7}{26}[/tex]
=0.269
The probability that both earrings are silver is 0.27.
