Answer:
The area of the paper on the bottom of the cage is [tex]270\ inch^{2}[/tex]
Step-by-step explanation:
Given:-
Volume of the cage = 6480 cubic inches.
Height of the cage = 24 inches.
Solution:-
[tex]Volume = l\times b\times h[/tex]
[tex]l\times b= \frac{V}{h} \\[/tex]
[tex]l\times b =\frac{6480}{24}[/tex]
[tex]l\times b = 270[/tex]--------------(equation 1)
Now,
Area of the bottom of the cage = [tex] l\times b[/tex]
Area of the bottom of the cage = [tex]270[/tex]------------(from equation 1)
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Therefore area of the bottom of the cage = [tex]270\ inch^{2}[/tex]
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