Respuesta :

The distance from (33, 5) to (33, -12) is 17 units

Solution:

Given that we have to find distance from (33, 5) to (33, -12)

Distance between two points [tex]P(x_1, y_1) \text{ and } Q(x_2, y_2)[/tex] is given by:

[tex]d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}[/tex]

Here the distance between (33, 5) and (33, -12) is given as:

[tex](x_1 , y_1) = (33, 5)\\\\(x_2 , y_2) = (33, -12)[/tex]

Substituting the values in above formula,

[tex]\begin{aligned}&d=\sqrt{(33-33)^{2}+(-12-5)^{2}}\\\\&d=\sqrt{0+(-17)^{2}}\\\\&d=\sqrt{289}\\\\&d=17\end{aligned}[/tex]

Thus the distance from (33, 5) to (33, -12) is 17 units

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