Answer:
[tex]y=-2x+19[/tex]
Step-by-step explanation:
we know that
The diagonals of a rhombus are perpendicular
so
diagonal DF is perpendicular to diagonal EG
see the attached figure to better understand the problem
The equation of the diagonal DF is [tex]y=\frac{1}{2}x-1[/tex]
The slope of the diagonal DF is [tex]m=\frac{1}{2}[/tex]
Remember that
If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)
so
The slope of the diagonal EG is equal to [tex]m=-2[/tex]
Find the equation in point slope form of the diagonal EG
[tex]y-y1=m(x-x1)[/tex]
we have
[tex]m=-2[/tex]
[tex]G(9,1)[/tex]
substitute
[tex]y-1=-2(x-9)[/tex]
Convert to slope intercept form
isolate the variable y
[tex]y-1=-2x+18[/tex]
[tex]y=-2x+18+1[/tex]
[tex]y=-2x+19[/tex]