What is the angular radius θ1 of the first dark ring for a point source being imaged by this telescope? Use 550 nanometers for the wavelength

Respuesta :

Answer:

Part D: 3.81 x 10^-5

Explanation:

There isn't enough information here to answer but a similar question came to me. I was given the same Wavelength, and a telescope diameter of 1.01m.

Equation: sinФ = 1.22 ( λ / D)

λ = 550 nm or 550 x 10^-9 m

D = 1.01 m (for the problem that I had)

So we need to find Φ, so we need to isolate that first. Using arcsin.

Arcsin = sin^-1 *Note this is not Sin raised to -1, this is arcsin put in this format to make it easier to put in your calculator*

Now we plug it into the equation.

Φ = 1.22 * sin^-1(550 x 10^-9 m / 1.01 m)

Φ = 3.806481985e -5⁰ (calculator answer)

also read as

Φ = 3.81 x 10^-5⁰ (Answer put into Mastering Physics)

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