Question

Write a balanced chemical equation for the equilibrium reaction occurring in a buffer containing nh3 and nh4cl. Write the equation so that its equilibrium constant is equivalent to ka.

Answer 1

Answer:

NH₃  +  H₂O  ⇄  NH₄⁺  +  OH⁻

NH₄⁺  + H₂O  ⇄   NH₃  +  H₃O⁺    Ka

Explanation:

Ammonia is a weak base

NH₃  +  H₂O  ⇄  NH₄⁺  +  OH⁻

It takes a proton from the water to make ammonium and hydroxide.

The salt NH₄Cl dissociates like this:

NH₄Cl  →  NH₄⁺  +  Cl⁻

Ammonium comes from a weak base, so it's a strong conjugate acid

Cl⁻ comes from a strong acid (HCl), so it's a weak conjugate base. It won't react in water.

Ammonium gives the proton to water, to make hydronium and ammonia, that's why you have Ka in the equilibrium, you are finally producing H₃O⁺.

Dont' never miss equilibrium of water

2H₂O ⇄  H₃O⁺ + OH⁻

Answer 2

The equations that can be used to obtain the Ka of the buffer is Ka = [NH3] [ H^+]/[NH4^+]

What is buffer?

A buffer is composed of a weak acid and its conjugate base or a weak base and its conjugate acid.

In this case, we have a weak base (NH3) and its conjugate acid (NH4^+). The acid base reaction that involves the species is;

NH3(aq) + H^+(aq) ⇄NH4^+

Hence Ka = [NH3] [ H^+]/[NH4^+]

Learn more about acid base: https://brainly.com/question/11934397