Question

Modern wind turbines are larger than they appear, and despite their apparently lazy motion, the speed of the blades tips can be quite high-many times higher than the wind speed. A turbine has blades 59 m long that spin at 14 rpm.
At the tip of a blade, what is the centripetal acceleration?

Answer 1

Answer:

Centripetal acceleration will be equal to $126.684rad/sec^2$

Explanation:

We have given length of the blade , that is radius r = 59 m

Angular speed $\omega =14rpm=\frac{2\times 3.14\times 14}{60}=1.4653rad/sec$

We have to find the centripetal acceleration

We know that centripetal acceleration is given by

$a_c=\frac{v^2}{r}=\omega ^2r$ ( as $v=\omega r$ )

So angular acceleration $a_c=1.4653^2\times 59=126.684rad/sec^2$

Centripetal; acceleration will be equal to $126.684rad/sec^2$