Answer:
[tex]7.14 m[/tex]
Step-by-step explanation:
Let x be the perimeter of the quarter circle.
Given:
The area of the quarter circle is [tex]3.14m^{2}[/tex]
We know area of the quarter circle is.
[tex]A=\frac{1}{4}\pi r^{2}[/tex]
Area of the quarter circle is given and [tex]\pi[/tex] value is 3.14.
[tex]3.14=\frac{1}{4}\times 3.14\times r^{2}[/tex]
[tex]\frac{3.14\times 4}{3.14}= r^{2}[/tex]
[tex]r^{2} =4[/tex]
[tex]r=2[/tex]
So, the radius of circle is [tex]2m^{2}[/tex]
The perimeter of the quarter circle is.
perimeter of quarter circle = [tex]2r+\frac{\pi r}{2}[/tex]
Put pie value is 3.14 and [tex]r=2m^{2}[/tex]} in above equation.
[tex]x=2\times 2 +\frac{3.14\times 2}{2}[/tex]
[tex]x=4 +\frac{3.14\times 2}{2}[/tex]
[tex]x=4+3.14[/tex]
[tex]x=7.14[/tex]
Therefore, the perimeter of the quarter circle is 7.14 m.