The light bulb produces 1.15 J energy in 1 second.
Explanation:
Efficiency of an electric appliance is defined as the ratio of output power to the input power. In a 100% efficient appliance all of the input power will be converted to output power. In the given question it is given that
input power= 10W
efficiency= 11.5%
(output power)/(input power)=efficiency
output power = input power * efficiency
[tex]=10 \times (11.5/100)=1.15W[/tex]
Now we have to calculate the energy produced by the light bulb in 1 second
[tex]energy=power \times time[/tex]
[tex]=1.15 \times 1[/tex]
=1.15J