Question

A rancher has 180 meters of fence with which to enclose three sides of a rectangular field (the fourth side is a cliff wall and will not require fencing). Find the dimensions of the field with the largest possible area. (For the purpose of this problem, the width will be the smaller dimension (needing two sides); the length with be the longer dimension (needing one side).)

Answer 1

Answer:

$90m\times 45 m$

Step-by-step explanation:

We are given that

Total length of fence=180 m

Let length of rectangular field=x

Width of rectangular field=y

According to question

Length of fencing=x+2y

$180=x+2y$

$x=180-2y$

Area of rectangular field=$length\times breadth$

Area of rectangular field=$x\times y$

$A=y(180-2y)$

$A(y)=180y-2y^2$

Differentiate w.r.t y

A'(y)=180-4y

A'(y)=0

180-4y=0

$4y=180$

$y=\frac{180}{4}=45$

Again differentiate w.r.t y

A''(y)=-4<0

Areas of rectangular field is minimum at y=45

Substitute the value then, we get

x=180-2(45)=90

Dimensions of rectangular field are 90 m by 45 m