Answer:
Length required will be 0.004 m
Explanation:
We have given efficiency of the reinforcement [tex]\eta =0.63[/tex]
We have to find the length required for the reinforcement
x is given x = 0.74 mm = [tex]0.74\times 106{-3}m[/tex]
x represent length of the fiber at each end
We know that efficiency is given by
[tex]\eta =\frac{l-2x}{l}[/tex]
So [tex]0.63=\frac{l-2\times 0.74\times 10^{-3}}{l}[/tex]
[tex]0.63l=l-0.00148[/tex]
[tex]0.37l=0.00148[/tex]
l= 0.004 m