Respuesta :
Answer:
[OH⁻] = 2,6x10⁻¹¹
Acidic
Explanation:
The kw in water is:
2 H₂O(l) ⇄ OH⁻(aq) + H₃O⁺(aq)
kw = [OH⁻] [H₃O⁺] = 1,00x10⁻¹⁴
If concentracion of H₃O⁺ is 3,9x10⁻⁴M:
[OH⁻] [3,9x10⁻⁴M] = 1,00x10⁻¹⁴
[OH⁻] = 2,6x10⁻¹¹
pH is defined as - log[H₃O⁺]. If pH>7,0 the solution is basic, if pH<7,0 solution is acidic, if pH=7,0 solution is neutral.
In this problem,
pH = - log [3,9x10⁻⁴M] = 3,4
As pH is < 7.0, the solution is acidic
I hope it helps!
A solution with [OH⁻] = 3.9 × 10⁻⁴ M, is also [H₃O⁺] = 2.6 × 10⁻¹¹ M and it is basic.
What is the ionic product of water?
The ionic product of water, Kw, is the equilibrium constant for the reaction in which water undergoes an acid-base reaction with itself.
We have a solution where the concentration of OH⁻ is 3.9 × 10⁻⁴ M. We can calculate the concentration of H₃O⁺ using the ionic product of water.
Kw = [H₃O⁺][OH⁻]
[H₃O⁺] = Kw / [OH⁻] = 1.0 × 10⁻¹⁴ / 3.9 × 10⁻⁴ = 2.6 × 10⁻¹¹ M
where,
- Kw is the ionic product of water.
- [H₃O⁺] is the concentration of hydronium ions.
- [OH⁻] is the concentration of hydroxyl ions.
Since [H₃O⁺] < 10⁻⁷ M, the solution is basic.
A solution with [OH⁻] = 3.9 × 10⁻⁴ M, is also [H₃O⁺] = 2.6 × 10⁻¹¹ M and it is basic.
Learn more about the ionic product of water here: https://brainly.com/question/15410096