Answer:
1) 0.51 seconds.
2) 1.45 m/s.
Explanation:
given, height from which cat falls = 1.3 m
we know that, s = ut + [tex]\frac{1}{2}[/tex]at².
here if we consider cat moment only in downward direction,
intial velocity of cat in downward direction , u = 0.
so, time, t = [tex]\sqrt{\frac{2h}{g} }[/tex].
⇒ t = [tex]\sqrt{\frac{2(1.3)}{9.81} }[/tex] = 0.51 seconds.
t = 0.51 seconds.
now, consider cat moment only in forward direction
s = ut , since acceleration is zero in forward direction
⇒ u = [tex]\frac{s}{t}[/tex].
so, u = [tex]\frac{0.75}{0.51}[/tex] = 1.45 m/s .