Question

Samuel is running in a park’s nature trail. At the first checkpoint, he ran 925 m in 10 minutes. At the second checkpoint, he slowed down and only ran 673 m in 13 minutes. What was the average velocity of Samuel’s entire trip (in m/s)?
2.38 m/s

1.16 m/s

3.18 m/s

1.89 m/s

Answer 1

Answer:

Average Velocity= 1.16m/s

Explanation:

Distance initially run= d1= 925m

distance finally run= d2= 673m

Time= t1= 10m

time= t2= 13m

Average Velocity= Total distance covered/ total time

                           =d1+d2/t1+t2

                  = 925+673/ 10(60) + 13(60)  {converting mins to secs)

                = 1598/1380= 1.157≅ 1.16m/s